Practice sheet Class Xth Chapter 16(Co-ordinate Geometry part I)

CO-ORDINATE GEOMETRY Part 1
( Conformed 3 mark Question)

1. Show that the points (0, – 1), (2, 1), (0, 3) and (– 2, 1) are the corners of a square.

idKwau ik ibMdU (0, – 1), (2, 1), (0, 3) Aqy(– 2, 1) ie`k vrg dy isKr hn [

2. Prove that the points (6, 9), (0, 1) and (– 6, –7) are collinear.

is`D kro ibMdU (6, 9), (0, 1) Aqy (– 6, – 7) smryKI hn [

3. Find the value of k, if the point P (0, 2) is equidistant from (3, k) and (k, 5).

Kdw mu`l pqw kro jykr ibMdU P (0, 2) ibMdUAW(3, k) Aqy (k, 5) qoN brwbr durI qy hovy [

4. Prove that the points A (0, 1), B (1, 4), C (4, 3), D (3, 0) are the vertices of a square.

idKwau ik ibMdU A (0, 1), B (1, 4), C (4, 3), D (3, 0) ie`k vrg ABCD dy isKr hn [

5. Find the point on x-axis which is equidistant from (– 2, 5) and (2, – 3).

xDury qy auh ibMdU pqw kro jo ibMdUAW (3,4) Aqy (2,-3) qoN brwbr dUrI qy hY [

6. Find the point on the y-axis which is equidistant from (– 5, – 2) and (3, 2).

yDury qy auh ibMdU pqw kro jo ibMdUAW (-5,-2) Aqy (3,2) qoN brwbr dUrI qy hY [

7. Show that the points (1, 0), (0, 1) and (– 3, 4) lie on a straight line.

is`D kro ibMdU (1,0), (0, 1) Aqy (– 3, 4) smryKI hn [

8. Find a point on the x-axis which is equidistant from the points (5, 4) and (– 2, 3).

xDury qy auh ibMdU pqw kro jo ibMdUAW (5,4) Aqy (-2,3) qoN brwbr dUrI qy hY [

9. Find the co-ordinates of the point which divides the line joining the points (3, 5), (4, 2) internally in the ratio 3 : 2.

aus ibMdU dy inrdyS AMk pqw kro jo (3, 5), (4, 2) nMU imlwaux vwly ryKw KMf nMU AMdrUnI 3:2 iv`c vMfdw hY [

10. Find the middle point of the line joining (– 3, – 6) and (1, – 2).

ibMdU (-3,-6), (1,-2) nMU imlwaux vwly ryKw KMf dy m`D ibMdU pqw kro[

11. Find the co-ordinates of the points which divides internally the line joining A(– 1, 2) to B (4, – 5) in the ratio 2 : 3.

aus ibMdU dy inrdyS AMk pqw kro jo A(– 1, 2) qoN B (4, – 5) nMU imlwaux vwly ryKw KMf nMU AMdrUnI 2:3 iv`c vMfdw hY [

12. In what ratio is the line joining the points A(4, 4) and B(7, 7) divided by P (–1, – 1)?

ibMdUAW A(4, 4) , B (7, 7 ) nMU imlwaux vwly ryKw KMf nMU ibMdU P (– 1, – 1) iks Anupwq iv`c vMfdw hY [